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IF a=log23 , b=log25, c=log72 , then find the value of log14063 in terms of a,b,c?
hi abhishek
log 140 63 = log2 63 / log2 140 = log2 ( 7 * 32 ) / log2 ( 7 * 5 * 22 ) eqn 1 ---- property of log
and 3 = 2 ^ a
5 = 2 ^ b and 7 = 2 ^ (1/c) ----- given information and definition of logarithm
putting the value in equation 1
(log2 7 + 3 * log2 3) / (log2 7 + log2 5 + 2 log2 2 )
put the values of 3 , 5 , 7 in terms of a , b , c
u will get {(1/c) + 3a} / { (1/c) + b + 2 }
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