Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

a square ABCD,has side length 4cm and M is the midpoint of side CD,a semi circle is drawn inside the square.Also with AB as radius an arc is drawn from B to D. The point of intersection of arc and semicircle is P.What is the distance from P to AD?

a square ABCD,has side length 4cm and M is the midpoint of side CD,a semi circle is drawn inside the square.Also with AB as radius an arc is drawn from B to D. The point of intersection of arc and semicircle is P.What is the distance from P to AD?

Grade:12

1 Answers

Akash Kumar Dutta
98 Points
8 years ago

Dear Ashwen,
Taking D as origin...
equation of the quadrant=x^2 + (y-4)^2=4^2
for the semicirle..= (x-2)^2 + y^2=2^2
Hence solving them and getting the point of intersection a (16/5,8/5)
Hence distance from AD= distance from y axis=x coordinate=16/5=3.2 units (ANS).
Regards.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free