Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

The number of ways in which a mixed double game can be arranged amongst 9 married couples if no husband and wife play in the same game is (a) 2 . 9 C 2 . 7 C 2 (b) 1512 (c) 3024 (d) None of these

The number of ways in which a mixed double game can be arranged amongst 9 married couples if no husband and wife play in the same game is


(a) 2 . 9 C 2 . 7  C 2            (b) 1512        


(c) 3024                             (d) None of these

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
11 years ago

Dear sanchit

out of 9 ,two men can be selected in 9 C 2 ways

now we can select from 7 women only because 2 women are the wife selected men

  =7  C 2

and from these 2 men and 2 women 4 combination is possible to make a team

so number of game =4 * 9 C 2   7  C 2

                            =3024


Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free