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No. of real roots of this equation are?
only 1 real root which is positive....
heres a trick for it...
in any equation to find no. of real roots do this
count the alternating signs as in this 35x-16 have alternate signs...the number of alternate signs tells us no.of positive roots..
now replace x by -x in the equation
we will get -7x^5-35x-16=0
as there isnt a alternate signs hence it wont have any negative roots..
hence we get only one root which is positive...
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