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the larger of the two angles made with the x axis of a straight line drawn through [1,2]so that it intersect x+y=4 at a distance root6/3 from [1,2] is
Dear jauneet singh here distance form of a line is very helpful equation of line (x-1)/ =(y-2)/sinΘ =√6 /3 so x=1+√6 cosΘ /3 and y =2 +√6 sinΘ /3 These point lie on the line x+y =4 so 1+√6 cosΘ /3 +2 +√6 sinΘ /3 =4 or √6 /3 (cosΘ +sinΘ) =1 or 1/√2 (cosΘ +sinΘ) =√3 /2 or sin(Θ+45) =sin 60 or sin 120 for larger angle sin(Θ+45) =sin 120 Θ=75 Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards, Askiitians Experts Badiuddin
Dear jauneet singh
here distance form of a line is very helpful
equation of line
(x-1)/ =(y-2)/sinΘ =√6 /3
so x=1+√6 cosΘ /3
and y =2 +√6 sinΘ /3
These point lie on the line x+y =4
so 1+√6 cosΘ /3 +2 +√6 sinΘ /3 =4
or √6 /3 (cosΘ +sinΘ) =1
or 1/√2 (cosΘ +sinΘ) =√3 /2
or sin(Θ+45) =sin 60 or sin 120
for larger angle
sin(Θ+45) =sin 120
Θ=75
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards, Askiitians Experts Badiuddin
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