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A car is parked by a driver amongst 25 cars in a row, not at either end. When he returns he finds that 10 places are empty. The probability that both the neighbouring places of drivers car are vacant, is???Pls explain how???

A car is parked by a driver amongst 25 cars in a row, not at either end. When he returns he finds that 10 places are empty. The probability that both the neighbouring places of drivers car are vacant, is???Pls explain how???

Grade:12th Pass

2 Answers

jitender lakhanpal
62 Points
10 years ago

Dear,

answer is C(23,8) / C (25,10)

for solution

 please find the attachment

 

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Kunal Upadhyay
38 Points
4 years ago
Since the owner finds on return that exactly 10 of the 25 Places(inckuding owner’s car) are occupied, the exhaustive no. of cases for such an arrangement is (25-1)C(10-1) = 24C9   [ since the remaining 9 cars to be parked in remaining 24 places]
Let E denote the event that both neighbouring places to owner’s car are empty. This require thr remaning 9 cars to be parked in remainig (25-3)=22 Places and hence the no of cases favourabke to E is 22C9 . Hence,
P(E) = 22C24C9 = 35/92 = 0.38043 Ans.

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