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If (x+y)/(x-y)=3, what is [(x^3+y^3)/(x^3-y^3)][(x^2+y^2)/(x^2-y^2)][(x+y)/(x-y)]?
Hi Red Dane,
This problem would require a little bit of manupilation of the given condition (a good trick).
As (x+y)/(x-y) = 3 we will have 3x+3y = x-y or 2x=4y or x/y=2....
So with x/y=2,
The required expression is:
[ {(x/y)3+1}/{(x/y)3-1} ] [ {(x/y)2+1}/{(x/y)2-1} ] [ {(x/y)+1}/{(x/y)-1} ].
Substitute for x/y = 2, and get the answer.
It will be 9/7 * 5/3 * 3 = 45/7.
Hope it helps.
Wish you all the best.
Regards,
Ashwin (IIT MadraS).
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