Use Coupon: CART20 and get 20% off on all online Study Material

Total Price: Rs.

There are no items in this cart.
Continue Shopping
harshit agarwal Grade: 12

If (cosx+sin(ax) is a periodic function and a is a root of equation x2+px+q=0 where p,q belong to integers , then show that pq cannot be an odd integer.

8 years ago

Answers : (1)

askIITiansexpert nagesh
16 Points

Dear harshit agarwal,

Given (cosx+sin(ax)) is a periodic function

This implies that 'a' should be rational.

'a' is root of x2+px+q=0, where p, q are integers.

As 'a' is rational number, let us consider a = m/n, where m,n are coprimes.

(m/n)2 + p(m/n) + q = 0.

m2 + pmn + qn2 = 0

m2 = -n(pm+qn)

hence m should be divisible by n, but m,n are coprimes, hence n=1, hence the equation will be

m2 +pm + q = 0, m is an integer.

q = -m(m+p)

It is clear that q is divisible by m.

If m is even then q is even and p can be even or odd.

If m is odd and p is odd then q is even

If m is odd and p is even then q is odd.

These are possible cases which doesn't include the case in which both q, p are odd.

if q is odd, then m should be odd and m+p should be odd

i.e., if q is odd, then m should be odd and p should be even.

Hence, pq cannot be odd integer.


Please feel free to post as many doubts on our discussion forum as you can. If you find any question

Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We

are all IITians and here to help you in your IIT JEE preparation. All the best harshit agarwal



Askiitians Experts





8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete JEE Main/Advanced Course and Test Series
  • OFFERED PRICE: Rs. 15,900
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

Answer ‘n’ Earn
Attractive Gift
To Win!!! Click Here for details