find the least no which when divided by 17 ,16,15 and the remainder is 3.10,0 respectively means u have to find

that no which is divided by 17 then it leaves the remainder

3 when divided by 16 leaves remainder 10 and when divi

ded by 15 leaves remainder 0

The code for the above problem is written in python as follos

for x in range(0,1000):
    a=15*x
    y=a%16
    if y==10 :
        z=a%17
        if z==3:
            print(a)

The output of the above code is

3930
8010
12090

so the least possible value is 3930

the ans which u provide that is wrong this ans is not satisfying my condition plz improve it 

We can  find the value using c program.....

#include<stdio.h>

#include<conio.h>

#include<math.h>

main()

{     

int a,x,y,z,n;     

x=0;     

y=3;     

z=10;              

for(a=0;a<=100;a++)

{

  if((y==a%17) && (z==a%16) && (x==a%15))

printf("%d",a);

}

getch();

}

we can get the output as 3930 and 8010 (from 0 to 10000) 

so the lowest number is 3930