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```        Here is Question .....
x + y + z = 2
x - y + z = 1
x - y - z = 1

solve for x, y and z```
10 years ago

```							This Question is quite simple ....i solved it ...  check out the solution
equation 1 + equation 2
=>       2(x+z) = 3
x+z = 3/2
equation 1 +equation3
=>       2x = 3
=>       x = 3/2
equation 2+quation3
=>       2(x-y) =1
x-y = 1/2
y = 1
equationj 1 substitute the values of x and y
=>        z=-1/2
```
10 years ago
```
x+y+z = 2  ;   x-y+z=1 ;  x-y-z=1
x+y+z+x-y+z=3
2(x+z) = 3
x+z=3/2
x+y+z+x-y-z = 3
2x =3
x=3/2
3/2+z=3/2
z=0
x-y-z=1
3/2-y-0=1
y=1/2
(x,y,z) = (3/2,1/2,0)
```
10 years ago
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