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Here is Question .....
x + y + z = 2 x - y + z = 1 x - y - z = 1
solve for x, y and z
This Question is quite simple ....i solved it ...
check out the solution
equation 1 + equation 2
=> 2(x+z) = 3 x+z = 3/2 equation 1 +equation3
=> 2x = 3 => x = 3/2 equation 2+quation3
=> 2(x-y) =1 x-y = 1/2 y = 1 equationj 1 substitute the values of x and y
=> z=-1/2
x+y+z = 2 ; x-y+z=1 ; x-y-z=1
x+y+z+x-y+z=3
2(x+z) = 3
x+z=3/2
x+y+z+x-y-z = 3
2x =3
x=3/2
3/2+z=3/2
z=0
x-y-z=1
3/2-y-0=1
y=1/2
(x,y,z) = (3/2,1/2,0)
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