Suppose Z1,Z2 and Z3 are vertices of an equilateral tirangle inscribed in a circle |Z|=2. If Z1=1+3i, then find Z2 and Z3.

The point Z₁( 1+3i) doesnot lie on circle |z|= 2

assuming the pt Z₁ as ( 1 + 3^1/2.i) , the problem is solved

Z₁ is at 60^o from origin, Z₂ will be at 180^o and Z₃ will be at 300^o

so Z₂ will be (-2 ,0)

and Z₃ will be ( 1 - 3^1/2.i)

Z₂  (-2 +0.i)
 Z₃  ( 1 - 3^1/2.i)

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