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A die is tossed twice. A is the event 'the sum of the two numbers uppermost is greater than 5' .B the event 'the sum of thw two numbers uppermost is less than 8'.Find the probability of these events.(a ) A(b ) B( c) AB( d) A U BHence show that P(A U B) =P(A) + P(B) - P(A ∩ B) .Are A and B mutually eclusive?
Dear student,
The correct option is c)
(a) The probability of A taking place, P(A)= 5/9
(b) The probability of B taking place, P(B)= 7/12
(c) P(AB) = 5/18
(d) P(A U B) = 31/36
P( A U B) = 31/36
P(A)= 5/9
P(B)= 7/12
P( A intersection B) = 5/18
As, 5/9 + 7/12 - 5/18= 31/36
Hence, P(A U B) = P(A) + P(B) - P( A intersection B)
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