Which iss greater 2^{30 OR} 3^20....HOW?

USING LOGARITHM

let 2³⁰ = x

=>30 log 2 = log x........(1)

again 3²⁰ = y

=>20 log 3 = log y.........(2)

now (1)/(2) =>

logx/logy <1

=>logy > logx

=> y>x

so 3^20 > 2^30