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Which iss greater 230 OR 320....HOW?
USING LOGARITHM
let 230 = x
=>30 log 2 = log x........(1)
again 320 = y
=>20 log 3 = log y.........(2)
now (1)/(2) =>
logx/logy <1
=>logy > logx
=> y>x
so 3^20 > 2^30
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