Find the sum of the positive integral divisors of

9999.........99 (2010 times)

Hello student,
Please find the answer to your question below
We can find the sum of positive integral divisors of any number by prime factorization of the number and following a formula
For example take a number 12
Its divisors are 1,2,3,4,6,12
SO its sum=28
it can also be found out by prime factorization of 12=2²X3¹
no of positive integral divisors=((2²⁺¹-1)/2-1)+(3¹⁺¹-1)/(3-1)=28
IN same way 999.....999(2010 times)
we get its prime factorization as 3²X1111111.....(2010 times )
As it is a very big number you can find it yourself after following similar procedure