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there are 11 identical balls to be placed in 3 bags such that sum of no. of balls in 2 bags is greater than no. of balls in other bag.in how many ways
ans is 15
let x,y and z be no. of balls in 3 bags
x+y+z=15
min. of x/y/z is 1 and max. is 5
→ 1 ≤ x,y,z ≤ 5
hence no. of ways of req. distribution is co-eff of x11 in (x+x2+x3+x4+x5)3
→ co-eff of x8 in (1+x+x2+x3+x4)3 = 15
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