If c, d are the roots of x2-10ax-11b=0 and a, b are the roots of x2-10cx-11d=0 then value of “a + b + c + d” isa) 1210b) -1c) 2530c) -11

Dear student,

a² - 10acx - 11d = 0

c² - 10acx - 11b = 0

subtract them ......

a² - c² = 11 ( d - b )    ........ (1)

a + b = 10c, ab = - 11d,

c + d = 10a, cd =  - 11b

a + b + c + d  = 10 ( a + c ) ...... (2)

b + d = 9 ( a + c ) ....... (3)

Also,   abcd = 121bd

so  ac = 121

from result (1) & (3)  ..... 

( b + d ) ( a - c ) / 9 = 11 ( d - b )

 ( a - c ) / 99 = ( d - b ) / ( b + d )

Simplifying. ...........

a² + c²  - 20 ac - 11 ( b + d ) = 0

( a + c )² - 22ac - 11 ( a + c ) 9 = 0

substutuing dat ac = 121

u get

finally

(a+c)² - 99 (a+c) - 2662 = 0

This is a quadratic in a+c

solving u get

a  +  c = 121

Go to result  :::

a + b + c + d = 10 ( a + c )  = 1210

Approved