Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
If c, d are the roots of x2-10ax-11b=0 and a, b are the roots of x2-10cx-11d=0 then value of “a + b + c + d” is a) 1210 b) -1 c) 2530 c) -11
If c, d are the roots of x2-10ax-11b=0 and a, b are the roots of x2-10cx-11d=0 then value of “a + b + c + d” is
a) 1210 b) -1
c) 2530 c) -11
Dear student, a2 - 10acx - 11d = 0 c2 - 10acx - 11b = 0 subtract them ...... a2 - c2 = 11 ( d - b ) ........ (1) a + b = 10c, ab = - 11d, c + d = 10a, cd = - 11b a + b + c + d = 10 ( a + c ) ...... (2) b + d = 9 ( a + c ) ....... (3) Also, abcd = 121bd so ac = 121 from result (1) & (3) ..... ( b + d ) ( a - c ) / 9 = 11 ( d - b ) ( a - c ) / 99 = ( d - b ) / ( b + d ) Simplifying. ........... a2 + c2 - 20 ac - 11 ( b + d ) = 0 ( a + c )2 - 22ac - 11 ( a + c ) 9 = 0 substutuing dat ac = 121 u get finally (a+c)2 - 99 (a+c) - 2662 = 0 This is a quadratic in a+c solving u get a + c = 121 Go to result ::: a + b + c + d = 10 ( a + c ) = 1210
Dear student,
a2 - 10acx - 11d = 0 c2 - 10acx - 11b = 0 subtract them ...... a2 - c2 = 11 ( d - b ) ........ (1) a + b = 10c, ab = - 11d, c + d = 10a, cd = - 11b a + b + c + d = 10 ( a + c ) ...... (2) b + d = 9 ( a + c ) ....... (3) Also, abcd = 121bd so ac = 121 from result (1) & (3) ..... ( b + d ) ( a - c ) / 9 = 11 ( d - b ) ( a - c ) / 99 = ( d - b ) / ( b + d ) Simplifying. ........... a2 + c2 - 20 ac - 11 ( b + d ) = 0 ( a + c )2 - 22ac - 11 ( a + c ) 9 = 0 substutuing dat ac = 121 u get finally (a+c)2 - 99 (a+c) - 2662 = 0 This is a quadratic in a+c solving u get a + c = 121 Go to result ::: a + b + c + d = 10 ( a + c ) = 1210
a2 - 10acx - 11d = 0
c2 - 10acx - 11b = 0
subtract them ......
a2 - c2 = 11 ( d - b ) ........ (1)
a + b = 10c, ab = - 11d,
c + d = 10a, cd = - 11b
a + b + c + d = 10 ( a + c ) ...... (2)
b + d = 9 ( a + c ) ....... (3)
Also, abcd = 121bd
so ac = 121
from result (1) & (3) .....
( b + d ) ( a - c ) / 9 = 11 ( d - b )
( a - c ) / 99 = ( d - b ) / ( b + d )
Simplifying. ...........
a2 + c2 - 20 ac - 11 ( b + d ) = 0
( a + c )2 - 22ac - 11 ( a + c ) 9 = 0
substutuing dat ac = 121
u get
finally
(a+c)2 - 99 (a+c) - 2662 = 0
This is a quadratic in a+c
solving u get
a + c = 121
Go to result :::
a + b + c + d = 10 ( a + c ) = 1210
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -