1+5+3+9+5+13+7+.................20terms = ?
1+5+3+9+5+13+7+.................20terms = ?
Raunak Kumar , 15 Years ago
Grade 11
Algebra> Q of Progression...
2 Answers
vikas askiitian expert
1 + 5 + 3 + 9 + 5 + 13 + 7 ...........
dividing this series in two series
S = [1 + 3 + 5 ........10 terms] + [5 + 9 + 13 .........10terms]
now we have two AP series , sum of each will be n/2 [ 2a + (n-1)d]
= 5[2+9*2] + 5[10 + 9*4]
=5 [ 20 + 46 ]
= 330
this is the required ans
Approved Last Activity: 15 Years ago
Raunak Kumar
thank you very much .!
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