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if the equations x2-3x-k=0 and 4x2-11x+2k=0have a common root then find the value of k.also find theb common root? if the equations x2-3x-k=0 and 4x2-11x+2k=0have a common root then find the value of k.also find theb common root?
if the equations x2-3x-k=0 and 4x2-11x+2k=0have a common root then find the value of k.also find theb common root?
let c is the common root then c will stisfy both of these equations . x2-3x-k = 0 .............1 4x2-11x+2k = 0 ............2 at x = c ,eq 1 becomes c2-3c-k = 0 2c2 - 6c - 2k = 0 ..............3 (after multiplying by 2) at x = c, eq 2 becomes 4c2-11c+2k = 0 ................4 adding 3 & 4 6c2 -17c = 0 c = 0 , 17/6 now , put c in any eq 3 or 4 then , k = 0,-17/36 (c,k) = { (0,0) ,(17/6,-17/36) } this is the required solution ... approve if u like my ans
let c is the common root then c will stisfy both of these equations .
x2-3x-k = 0 .............1
4x2-11x+2k = 0 ............2
at x = c ,eq 1 becomes
c2-3c-k = 0
2c2 - 6c - 2k = 0 ..............3 (after multiplying by 2)
at x = c, eq 2 becomes
4c2-11c+2k = 0 ................4
adding 3 & 4
6c2 -17c = 0
c = 0 , 17/6
now , put c in any eq 3 or 4
then , k = 0,-17/36
(c,k) = { (0,0) ,(17/6,-17/36) }
this is the required solution ...
approve if u like my ans
Take both as equations x2-3x-k = 0 .............1 4x2-11x+2k = 0 ............2 Solve it by eliminating method: 2x2-6x-2k = 0 [multiply by 2}........(3) now from eq. (2) and (3) 4x2-11x+2k = 0 2x2-6x-2k = 0 Solving these equations by eliminating method u will get: 6x2-17x = 0 .....................(4) x(6x-17) = 0 6x = 17 x = 0, 17/6 Put the value of x in eq...........(4) k = 0,-17/36 then, (c,k) = { (0,0) ,(17/6,-17/36) }
Take both as equations
Solve it by eliminating method:
2x2-6x-2k = 0 [multiply by 2}........(3)
now from eq. (2) and (3)
4x2-11x+2k = 0
2x2-6x-2k = 0
Solving these equations by eliminating method u will get:
6x2-17x = 0 .....................(4)
x(6x-17) = 0
6x = 17
x = 0, 17/6
Put the value of x in eq...........(4)
k = 0,-17/36
then,
x2 -4x+k = 0 and x2+kx-4 =0 have a common root, so let’s take it yputting value of yy2-4y+k=0 ----{1}y2-ky+4=0 ------{2}substracting {1} from {2}y2-4y+k-[ y2-ky+4]y2-4y+k-y2+ky-4=0-y(k+4)+4+k=04+k= y(k+4)y=1putting y=1 in eq {1}y2-4y+k=0(1)2-4(1)+k=01-4+k=0k=3
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