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solve for x: (log 10 x) 2 - (log 10 x) - 6 =0 i have solved the answer as follows: let log 10 x = y therefore, y 2 - y - 6 = 0 y 2 - 3y + 2y - 6 = 0 y(y - 3) + 2(y - 3) = 0 y + 2 = 0 or y - 3 =0 y = -2 or y = 3 thus, log 10 x = -2 or log 10 x = 3 10 -2 = x or 10 3 = x x = 0.01 or x = 1000 is my solution right, or are there more values of x??? plzzz tell....

solve for x:


(log10x)2 - (log10x) - 6 =0


i have solved the answer as follows:


let log10x = y


therefore, y2 - y - 6 = 0


               y2 - 3y + 2y - 6 = 0


               y(y - 3) + 2(y - 3) = 0


              y + 2 = 0   or   y - 3 =0


              y = -2      or   y = 3


thus, log10x = -2    or   log10x = 3


        10-2 = x        or      103 = x


        x = 0.01        or       x = 1000


is my solution right, or are there more values of x???  plzzz  tell....

Grade:11

2 Answers

vikas askiitian expert
509 Points
12 years ago

your ans is correct , no other value for x is possible...

Surbhi Kumari
29 Points
12 years ago

i think that the solution is right and there are no more values of x

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