A gambler rolls two dice and stands to loss Rs.2/- if he fails to throw a six ; to win
Rs.4/- he must throw one six and to win Rs.10/- he must throw 2 sixes. Is the game
fair?

Question

A gambler rolls two dice and stands to loss Rs.2/- if he fails to throw a six ; to win Rs.4/- he must throw one six and to win Rs.10/- he must throw 2 sixes. Is the game fair?

Jitender Singh · Answer

Ans:
Hello Student,
Please find answer to your question below

Total number of possibilities on two dice
36
Number of possibilities with 6 on both dice
1
Number of possibilities with 6 on one dice
10
Number of possibilities with 6 on neither of dice
25
So lets calculate the amount of the money
$25\times 2 = Rs.50$
$(10\times 4)+(1\times 10) = Rs.50$
Both amount are same for winning and losing.
So the game is fair.

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A gambler rolls two dice and stands to loss Rs.2/- if he fails to throw a six ; to win Rs.4/- he must throw one six and to win Rs.10/- he must throw 2 sixes. Is the game fair?

A gambler rolls two dice and stands to loss Rs.2/- if he fails to throw a six ; to win
Rs.4/- he must throw one six and to win Rs.10/- he must throw 2 sixes. Is the game
fair?

1 Answers

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