The equations x^2 + b^2 = 1- 2bx and x^2 + a^2 = 1- 2ax have a common root. IF a AND b ARE NOT EQUAL, then prove that

mod. of (a-b) = 2.

Dear shirdhar

Roots of first euqtion are -1-b,1-b

second one ra -1-a and 1-a

so -(1+b)=(1+a)

or 1-b =-1-a

b-a = 2

symmetry you get a-b=2

so mod (a-b)=2

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