Grade 12th PassAlgebra
The sum of the binomial coefficients of  is equal to 256 . The constant term in the expansion is |
||
| 1120 | ||
| 2110 | ||
| 1210 | ||
| none | ||
1 Answer
Nehal Wani
[2x+1/x]n
Sum of binomial coefficients:
nC0+ nC1+ nC2+ nC3+………………….+ nCn+ nCn=2n
256=2n
Therefore n=8
Tr=nCr(2x)n-r(x)-r= nCr2n-rxn-2r= 8Cr28-rx8-2r
8-2r=0
⇒ r=4
8Cr28-rx8=8C424=1120
Other Related Questions on algebra
How do you write “the product of 18 and q” as an algebraic expression?
How do you write “the product of 18 and q” as an algebraic expression?
algebra
Last Activity: 2 Years ago