The sum of the binomial coefficients of  is equal to 256 . The constant term in the expansion is |
||
| 1120 | ||
| 2110 | ||
| 1210 | ||
| none | ||
VISHWESH RAVI , 14 Years ago
Grade 12th Pass
Algebra> please help...
1 Answers
Nehal Wani
Last Activity: 14 Years ago
[2x+1/x]n
Sum of binomial coefficients:
nC0+ nC1+ nC2+ nC3+………………….+ nCn+ nCn=2n
256=2n
Therefore n=8
Tr=nCr(2x)n-r(x)-r= nCr2n-rxn-2r= 8Cr28-rx8-2r
8-2r=0
⇒ r=4
8Cr28-rx8=8C424=1120
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