The number of ways in which a mixed double game can be arranged from amongst 9 married couples if no husband and wife play in the same game is? I have gotten an answer for this question, but even after seeing it I still have a doubt. Could you please help? The answer I have been given is what i arrived at myself on first encountering the question, but on 2nd thoughts, i felt that besides the case of 2 men being chosen out of 9 and then 2 women being selected out of 7, there is also the possible case of 2 women being selected out of 9 and then 2 men being selected out of 7 and also the third case of 2 men being selected out of eight and then 2 women being selected out of 8 , i.e, a husband from 1 couple and a wife from another couple play the game. why aren't these 2 cases being considered?
The number of ways in which a mixed double game can be arranged from amongst 9 married couples if no husband and wife play in the same game is? I have gotten an answer for this question, but even after seeing it I still have a doubt. Could you please help? The answer I have been given is what i arrived at myself on first encountering the question, but on 2nd thoughts, i felt that besides the case of 2 men being chosen out of 9 and then 2 women being selected out of 7, there is also the possible case of 2 women being selected out of 9 and then 2 men being selected out of 7 and also the third case of 2 men being selected out of eight and then 2 women being selected out of 8 , i.e, a husband from 1 couple and a wife from another couple play the game. why aren't these 2 cases being considered?
