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21x^2-16/3x^2-4 -7x=5 find or solve for the value of x in the above equation
21x^2-16/3x^2-4 -7x=5 find or solve for the value of x in the above equation


4 years ago

HARISH SAHU
21 Points
							Given Equation is$21x^2 - \frac{16}{3}x^2 -4 -7x =5$both side multiply by 3 $63x^2 -16x^2 -12-21x =15$arranging simila terms$47x^2 -21x -27 =0$after solvingx1 = 1.0135798980727626 and x2 = -0.5667713874344646.........Ans

4 years ago
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• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions