(1+x)^2016 [{(x/(x+1))^2017 – 1} / {(x/x+1) – 1}] = {(1+x)^2017 – x^2017} How?? please show the steps....

Question

(1+x)^2016 [{(x/(x+1))^2017 – 1} / {(x/x+1) – 1}] = {(1+x)^2017 – x^2017} How?? please show the steps....

Saurabh Koranglekar · Answer

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(1+x)^2016 [{(x/(x+1))^2017 – 1} / {(x/x+1) – 1}] = {(1+x)^2017 – x^2017} How?? please show the steps....

(1+x)^2016 [{(x/(x+1))^2017 – 1} / {(x/x+1) – 1}] =
{(1+x)^2017 – x^2017}
How?? please show the steps....

1 Answers

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(1+x)^2016 [{(x/(x+1))^2017 – 1} / {(x/x+1) – 1}] = {(1+x)^2017 – x^2017} How?? please show the steps....

(1+x)^2016 [{(x/(x+1))^2017 – 1} / {(x/x+1) – 1}] = {(1+x)^2017 – x^2017}How?? please show the steps....

1 Answers

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(1+x)^2016 [{(x/(x+1))^2017 – 1} / {(x/x+1) – 1}] =
{(1+x)^2017 – x^2017}
How?? please show the steps....