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`        (1-w+w^2) (1-w^2+w^4) (1-w^4+w^8) to 2n factors is   a)2 b)2^2n c)2n d)2^n`
5 months ago

Vikas TU
9814 Points
```							Dear student The ans woud be (x-1)^2nw^1 = w w^2 = ww^4 = w w^8 = w^6+w^2 = w^22^n = 3n , 3n + 1 , 3n +21+w+w^2 = 0 => (x-1)(x-1)(x-1)......2n => (x-1)^2n is ans
```
5 months ago
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### Course Features

• 101 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions