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1)find the least value of 6x 2 -22x+21/5x 2 -18x+17 for real x 2)solve for x (x 2 -4x) 2 – (x-2) 2 – 16 = 0 3)the cartesian product of A*A has 9 elements among which are found (-1,0) and (0,1). find the set A 4)Find the domain fo the function f(x) = 1/sq root x-IxI. these are cbse questions so pls give answers with steps
1)find the least value of 6x2-22x+21/5x2-18x+17 for real x2)solve for x (x2-4x)2 – (x-2)2 – 16 = 03)the cartesian product of A*A has 9 elements among which are found (-1,0) and (0,1). find the set A4)Find the domain fo the functionf(x) = 1/sq root x-IxI.these are cbse questions so pls give answers with steps

```
4 years ago

Vikas TU
14149 Points
```							 6x2-22x+21/5x2-18x+1to minimise it maximise the denominator and minimise the numerator simultaneously.Therefore,N(x) =  6x2-22x+21N(x)’ = 12x – 22 N(x)’’ =  12 > 0 .i.e 12 x – 22 =0x = 11/6 is the minima point.D(x) = 5x2-18x+1D(x)’ = 10x – 18D(x)’’ = 10 > 0 thus,10 x – 18 = 0x = 9/5 is the minima point but we want to maximis ethe denominator therefore, neglecting x = 9/5.Put x = 11/6 in  6x2-22x+21/5x2-18x+1 that would be the minum vale of the expression.
```
4 years ago
Vikas TU
14149 Points
```							Dear raghav,plz put your questions in sequence wise at once.At one time post your question as a one time.In that way it would be easy for us to answer sequentially.Thankyou!
```
4 years ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
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• Previous Year Exam Questions