#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Click to Chat

1800-5470-145

+91 7353221155

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# three charges q, Q and 4q are placed in a straight line of length L at points distant 0, L/2 and L respectively. Find the value of Q for which charges will remain stationary. Options q/root3, qRoot3, -q root3, -q/root3

sree lakshmi
73 Points
2 years ago
for the charges to remain stationary the system should be in equilibrium
in this question q and 4q are +ve and they repel each other so the system to be in equilibrium the Q should be -ve so that
-Q attract q and 4q
if we consider q at (0,0) force on it are repulsion by 4q and attraction by -Q  these two forces should be equal for q to remain stationary
ie    $k q*Q/(L/2)^2$ = $k q*4q/(L)^2$
$\Rightarrow$ 4Q/L = 4q/L2
$\Rightarrow$Q = q       ie Q = -ve q