The velocity v of a particle moving along x axis varies with its position x as shown in figure. The acceleration of a particle varies with position as

Question

Eshan · Answer

Dear student, Acceleration of a particle= Velocity as a function of displacement can be writtten from the given figure as- Hence

Rajat · Answer

a==dv/dt dv/dx×dx/dt a=vdv/dx From graph dv/dx=2 a=-2v........1 - indicates line of graph Now using eqn of slope y=mx+c v=-2+4 - is due to negative slope a=-2(-2x+4) a=4x-8

Kushagra Madhukar · Answer

Dear student, Please find the solution to your problem. a = dv/dt dv/dx × dx/dt a = vdv/dx From graph dv/dx = 2 a = – 2v ........1 – sign indicates line of graph Now using eqn of slope y = mx + c v = – 2x + 4 – sign is due to negative slope a = – 2(–2x + 4) a = 4x – 8 Thanks and regards, Kushagra

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The velocity v of a particle moving along x axis varies with its position x as shown in figure. The acceleration of a particle varies with position as

The velocity v of a particle moving along x axis varies with its position x as shown in figure. The acceleration of a particle varies with position as

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