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The pH of buffer solution prepared by mixing 50 ml of 0.2 molar acetic acid and 25 ml of Sodium Acetate is 4.8 then the concentration of Sodium Acetate is pka Of Acetic Acid equals to 4.8

Nayan , 5 Years ago
Grade 11
anser 1 Answers
Arun

Last Activity: 5 Years ago

Concentrations in the mixture: 

[CH3COOH] = 0.050*0.2/ 0.075 = 0.133 M 
[CH3COO-] = 0.025*x/0.075 = x/3 

pH = pKa + log[CH3COO-]/[CH3COOH] 

pKa = 4.76 
pH = 4.8 

0.04 = log[(x/3)/0.133] 
1.10 = x/0.40 
x = 0.44 

[CH3COO-] = x/3 = 0.15 M

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