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A simple pendulum of length L and bob of mass M if displaced from its equilibrium position O to a position P so that height of P above O is h. It is then released. What is the tension in the string when the bob passes through the equilibrium position O? neglect friction v is the velocity of the Bob at O.
Dear student Apply conservation of energy at A and B 0.5mv^2 + 0 = 0+ mgh V = 0 at B v^2 = 2gh Equation of motion at A ma = T-mg a = v^2/l = 2gh/lT =mg + m(2gh/l)T = mg(1+2h/l)Good Luck
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