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Grade 12th passAIPMT

A Particle is projected from ground at an angle theta with horizontal with speed u . The ratio of Radius of curvature of its trajectory at point of projection to radius of curvature at maximum height is ..........

Tanvir Alam

7 Years agoGrade 12th pass

2 Answers

Eshan

7 Years ago

ankit singh

5 Years ago

Given that,

Angle θ=450

Horizontal distance x=10m

Vertically distance y=7.5m

Acceleration due to gravity g=10m/s2

Now,

y=(tanθ)x−(2u2cos2θg)x2

7.5=1×10−(2u2×21)10×100

7.5−10=−u21000

u2=2.51000

u=20m/s

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