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A Particle is projected from ground at an angle theta with horizontal with speed u . The ratio of Radius of curvature of its trajectory at point of projection to radius of curvature at maximum height is ..........

Tanvir Alam , 6 Years ago
Grade 12th pass
anser 2 Answers
Eshan

Last Activity: 6 Years ago

568-2332_123.png

ankit singh

Last Activity: 4 Years ago

 

Given that,
Angle θ=450
Horizontal distance x=10m
Vertically distance y=7.5m
Acceleration due to gravity g=10m/s2
Now,
  y=(tanθ)x−(2u2cos2θg​)x2
 7.5=1×10−(2u2×21​)10​×100
 7.5−10=−u21000​
 u2=2.51000​
 u=20m/s

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