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A car moving along a straight line (without returning) travels distance equal to the numerical value of time elapsed in every second. If car starts at t = 0 with constant acceleration, the magnitude of initial velocity of the car is 1) 0.2 m/s 2) 0.5 m/s 3) 0.75 m/s 4) 1.0 m/s
Let it start with velocity u and acceleration a.For 1st second:v=u+at=u+as=(v2-u2)/2a=u+a/2=1For the 2nd second:v'=(u+a)t+at=u+2as'=u+3a/2=u+a/2+a=1+a=2(s'=2 as 2s has elasped).So 1+a=2Or,a=1.Putting it in the equation of s,u+a/2=1Or,u=1/2=0.5If it helps please approve.
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