A car moving along a straight line (without returning) travels distance equal to the numerical value of time elapsed in every second. If car starts at t = 0 with constant acceleration, the magnitude of initial velocity of the car is 1) 0.2 m/s 2) 0.5 m/s 3) 0.75 m/s 4) 1.0 m/s

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Susmita · Answer

Let it start with velocity u and acceleration a. For 1st second: v=u+at=u+a s=(v 2 -u 2 )/2a=u+a/2=1 For the 2nd second: v'=(u+a)t+at=u+2a s'=u+3a/2=u+a/2+a=1+a=2(s'=2 as 2s has elasped). So 1+a=2 Or,a=1. Putting it in the equation of s, u+a/2=1 Or,u=1/2=0.5 If it helps please approve.

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A car moving along a straight line (without returning) travels distance equal to the numerical value of time elapsed in every second. If car starts at t = 0 with constant acceleration, the magnitude of initial velocity of the car is 1) 0.2 m/s 2) 0.5 m/s 3) 0.75 m/s 4) 1.0 m/s

A car moving along a straight line (without returning) travels distance equal to the numerical value of time elapsed in every second. If car starts at t = 0 with constant acceleration, the magnitude of initial velocity of the car is

1) 0.2 m/s
2) 0.5 m/s
3) 0.75 m/s
4) 1.0 m/s

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A car moving along a straight line (without returning) travels distance equal to the numerical value of time elapsed in every second. If car starts at t = 0 with constant acceleration, the magnitude of initial velocity of the car is 1) 0.2 m/s 2) 0.5 m/s 3) 0.75 m/s 4) 1.0 m/s

A car moving along a straight line (without returning) travels distance equal to the numerical value of time elapsed in every second. If car starts at t = 0 with constant acceleration, the magnitude of initial velocity of the car is 1) 0.2 m/s2) 0.5 m/s3) 0.75 m/s4) 1.0 m/s

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A car moving along a straight line (without returning) travels distance equal to the numerical value of time elapsed in every second. If car starts at t = 0 with constant acceleration, the magnitude of initial velocity of the car is

1) 0.2 m/s
2) 0.5 m/s
3) 0.75 m/s
4) 1.0 m/s