Two identical wires of the same length are subjected to tension T1 and T2 and have natural frequency n1 and n2 then

Frequency= square root of (TL/M)/2LSo , frequency is directly proportonal to square root of Tension. n1/n2 = sqrt(T1/T2)Hope this helps Goos Luck

Two identical wires of the same length are subjected to tension T1 an

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Consider the situation shown in figure. The strings are massless and pulley is fixed and frictionless. The speed of 3 kg mass just before touching the ground is (g = 10 m s-²)

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100 ml of gaseous hydrocarbon consumes 300 ml of oxygen for complete combustion. the hydrocarbon is

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AIIMS MBBS> Two identical wires of the same length ar...

Two identical wires of the same length are subjected to tension T1 and T2 and have natural frequency n1 and n2 then

Shizakhan , 7 Years ago

Vikas TU

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most scoring topics for neet?for all the subjects : chemisrtry,biology and physics

aiims mbbs

Consider the situation shown in figure. The strings are massless and pulley is fixed and frictionless. The speed of 3 kg mass just before touching the ground is (g = 10 m s-²)

aiims mbbs

Hi! My son would be taking his exam in May 2022. We need some counseling as to how to go about it as an NRI?

aiims mbbs

aiims mbbs

100 ml of gaseous hydrocarbon consumes 300 ml of oxygen for complete combustion. the hydrocarbon is

aiims mbbs

AIIMS MBBS> Two identical wires of the same length ar...

Two identical wires of the same length are subjected to tension T1 and T2 and have natural frequency n1 and n2 then

Shizakhan , 7 Years ago

Vikas TU

LIVE ONLINE CLASSES

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