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Grade: 12th pass
        
Two identical wires of the same length are subjected to tension T1 and T2 and have natural  frequency n1 and n2 then 
one year ago

Answers : (1)

Vikas TU
8825 Points
							
Frequency= square root of (TL/M)/2L
So , frequency is directly proportonal to square root of Tension. 
n1/n2 = sqrt(T1/T2)
Hope this helps 
Goos Luck
one month ago
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