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Two identical wires of the same length are subjected to tension T1 and T2 and have natural frequency n1 and n2 then

Two identical wires of the same length are subjected to tension T1 and T2 and have natural  frequency n1 and n2 then 

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Grade:12th pass

1 Answers

Vikas TU
14149 Points
one year ago
Frequency= square root of (TL/M)/2L
So , frequency is directly proportonal to square root of Tension. 
n1/n2 = sqrt(T1/T2)
Hope this helps 
Goos Luck

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