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In a oscillatory system, the amplitude of motion is 5m and the time period is 4s. The time taken by the particle for passing between points which are at the distances of 4m and 2m from the centre and on the same side of it will be ?

vinushree , 6 Years ago
Grade 12th pass
anser 1 Answers
Arun

y = A sin ωt

ω= 2π/T , T is the period.

When y = 4m

4 = 5 sin ( 2π/4 ) *t1 =5 sin 1.571 t1

sin 1.571 t1 = 0.8

1.571 t1 =0.9272 radian

t1 = 0.590 s

When y = 2m

2 =5 sin 1.571 t2

t2 = 0.2619

Time difference is 0.59 - 0.26 = 0.33 s

Last Activity: 6 Years ago
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