Arun
Last Activity: 6 Years ago
Dear student
No of sides of the polygon is 360/60=6
We get a isosceles triangle inside a hexagon during his eighth turn. Interior angle of hexagon is 120°.
Leta perpendicular be dropped which divides his displacement into 2 halves. Let his displacement be d.Then sin60°=d/2÷10 Then d/2=10*sin 60°
d=2*10*sin 60°=17.32(approx)