Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A Man Moves in an open field such that after moving 10 m on a straight line , he makes a sharp turn of 60 degree to his left . The Total Displacement just at the start of 8th Turn is equal to ........ ????

A Man Moves in an open field such that after moving 10 m on a straight line , he makes a sharp turn of 60 degree to his left . The Total Displacement just at the start of 8th Turn is equal to ........ ????
 

Grade:12th pass

1 Answers

Arun
25763 Points
2 years ago
Dear student
 
 
No of sides of the polygon is 360/60=6
We get a isosceles triangle inside a hexagon during his eighth turn. Interior angle of hexagon is 120°.
Leta perpendicular be dropped which divides his displacement into 2 halves. Let his displacement be d.Then sin60°=d/2÷10  Then d/2=10*sin 60°
d=2*10*sin 60°=17.32(approx)

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free