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Grade: 11
        
A 2m long rod of radius 1cm which is fixed from one end is given a twist of 0.8 radius. The shear strain developed will be
  1. 0.002
  2. 0.004
  3. 0.008
  4. 0.016
3 months ago

Answers : (1)

Arun
18654 Points
							
Given : L = 2 m
                              r = 1cm = 10–2 m
                              twist = θ = 0.8 rad
                                 angle of shear = ɸ          = (rθ / L)
                                                            = {(10–2 × 0.8) / 2}
                                                            = 0.4 × 10–2
                              i.e. shear strain = 0.004 rad 
3 months ago
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