the roots of the eqation (x-1)^3+8=0 are

the roots of the eqation (x-1)^3+8=0 are


1 Answers

Badiuddin askIITians.ismu Expert
148 Points
14 years ago

Dear manan


by inspection we can easly find out that x=-1 is the root of equation

now f(x) = (x-1)^3+8

      f'(x) = 3(x-1)2

  f'(x) 0 for all x

so f(x) is a increasing function

so given function can cut x axix only 1 point ,equation has only one root = -1

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