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Grade 69 grade science

Starting from a distance of 20 meters to the left of the origin and at a velocity of 10 m/s, an object accelerates to the right of the origin for 5 seconds at 4 m/s2. What is the position of the object at the end of the 5 seconds of acceleration?

Profile image of Leena
8 Years agoGrade 6
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1 Answer

Profile image of Kushal Chaudhari
ApprovedApproved Tutor Answer8 Years ago
In this problem, we may consider that the direction of the object is the positive direction and the initial position x0 = -20 meters (to the left of the origin), the initial velocity u = 10 m/s, the acceleration a = 4 m/s2 and the time is t = 5 seconds. The position is given by 
 
x = (1/2) a t2 + u t + x0
 
= 0.5 * 4 * (5)2 + 10 * 5 - 20 = 80 meters to the right of the origin