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An echo repeats two syllables.If the velocity of sound is 330 m/s, then the distance of the reflecting surface is? An echo repeats two syllables.If the velocity of sound is 330 m/s, then the distance of the reflecting surface is?
Answer is 66mBecause velocity of sound is 330 m/s so the minimum distance required to hear sound is 330/10=33mFor one syllable 33m so for two syllables 66m
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