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0.202 gm of a carbon compound on combustion , gave 0.361 gm of carbon dioxide and 0.47 gm of water . calculate the percentage composition of carbon :
moles of CO2= 0.361/44 = 0.0082 mass of carbon = 0.0082 * 12 = 0.095845 percentage of carbon = 0.09845/0.202 * 100 = 48.73 %
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