Harshit Singh
Last Activity: 3 Years ago
Dear Student
Let the digit at tens place be x then digit at ones place will be (9-x).
Original two-digit number = 10x + (9-x)
After interchanging the digits, the new number = 10(9-x) + x
According to the question,
10x+(9-x)+27=10(9-x)+x
⇒10x+9-x+27=90-10x+x
⇒9x+36=90-9x
⇒9x+9x=90-36
⇒18x=54
⇒x=3
Originalnumber=10x+(9-x)=(10×3)+(9-3)=30+6=36
Thus, the number is 36.
Thanks