Grade 88 grade maths
solve the following using the standard identity (a+b)(a-b)=a2-b2104x96
solve the following using the standard identity (a+b)(a-b)=a2-b2
104x96
2 Answers
Arun
Dear student
We can write it as
104 X 96 = ( 100 + 4) X (100 -4)
This is the same form of (a+b) (a - b)
Which equals a² - b²
Hence
104 X 96 = (100 +4) X (100 - 4) = 100² - 4² = 10000 -16
= 9984
Regards
Arun (askIITians forum expert)
Sayantan Garai
104×96
=(100+4)(100-4)........(i)
Given eq.is (a+b)(a-b)....(ii)
Comparing,we get
a=100 and b=4
Hence, 96×104=(100+4)(100-4)=100²-4²=10000-16=9984.
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