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Dear Student5t–3=3t–5⇒ 5t- 3t = -5 + 3⇒ 2t =-2⇒ t =-1Putting the value of t in RHS and LHS we get,5× (-1) - 3 = 3× (-1) - 5⇒-5-3=-3-5⇒-8=-8⇒LHS=RHSThanks
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