The electric field at (30,30)cm due to charge of -8nC at the origin in NC -1

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Arun · Answer

Dear student E = kq * (r vector) /r³ I am getting my answer as 282.7 i + 282.7 j Hope it helps Regards Arun

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The electric field at (30,30)cm due to charge of -8nC at the origin in NC -1

The electric field at (30,30)cm due to charge of -8nC at the origin in NC^-1

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The electric field at (30,30)cm due to charge of -8nC at the origin in NC -1

The electric field at (30,30)cm due to charge of -8nC at the origin in NC-1

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The electric field at (30,30)cm due to charge of -8nC at the origin in NC^-1