A steady current of 0.80 ampere was passed through an aqueous solution of tetraoxosulphate (6) acid for 7 hours. Calculate the volume of hydrogen gas that was liberated at standard temperature and pressure

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Quantity of electricity =Q=Ampere&times;&times;Second &there4;Q=0.8&times;420&times;60= 20160 Coulomb Therefore, 11.2 dm 3 ofH 2 liberated by 96500 coulomb of electricity, Thereforex dm 3 ofH 2 liberated by 20160 coulomb of electricity . &there4; x=11.2 &times; 20160/96500= 2.34

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A steady current of 0.80 ampere was passed through an aqueous solution of tetraoxosulphate (6) acid for 7 hours. Calculate the volume of hydrogen gas that was liberated at standard temperature and pressure

A steady current of 0.80 ampere was passed through an aqueous solution of tetraoxosulphate (6) acid for 7 hours. Calculate the volume of hydrogen gas that was liberated at standard temperature and pressure

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A steady current of 0.80 ampere was passed through an aqueous solution of tetraoxosulphate (6) acid for 7 hours. Calculate the volume of hydrogen gas that was liberated at standard temperature and pressure

A steady current of 0.80 ampere was passed through an aqueous solution of tetraoxosulphate (6) acid for 7 hours. Calculate the volume of hydrogen gas that was liberated at standard temperature and pressure

1 Answers

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Other Related Questions on 6 grade science

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