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What is the electronic configuration of O 2 − ion? A 1 s 2 2 s 2 2 p 6 B 1 s 2 2 s 2 2 p 4 C 1 s 2 2 s 2 2 p 5 D 1 s 2 2 s 2 2 p 3 What is the electronic configuration of O2− ion?A1s22s22p6B1s22s22p4C1s22s22p5D1s22s22p3
Dear student O^2- refers oxide ion.The atomic number of oxygen is 8.The electronic configuration of Oxygen is1s^2 2s^2 2p^4The charge of oxide ion is —2, which means an Oxygen atom gained 2 extra electrons. So,this two extra electrons will be attached the last shell's orbital (2p).So, the electronic configuration of oxide ion is1s^2 2s^2 2p^6When any oxygen atom attach with any metal, oxygen atom gains two electrons from metal and forms oxide ion. In this attachment Ionic bond is formed Between oxygen and metal ion.Example :CaOCalcium atom donated two electrons & formed Ca^2+ (Calcium ion).Also gained the electronic configuration of inert gas (Ar)Oxygen atom gained those two electrons & formed O^2– (Oxide ion). Also gained electronic configuration of inert gas (Ne)Ca^2+ + O^2- → CaO (Calcium oxide)Here,Ionic bond is formed between calcium & oxygen.
O2−: The atomic number of O=8=number of electrons Number of electrons in O2− are 8+2=10 Electronic configuration will be 1s22s22p6
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