What is the electronic configuration of O2− ion?A1s22s22p6B1s22s22p4C1s22s22p5D1s22s22p3

Vikas TU
14149 Points
4 years ago
Dear student
O^2- refers oxide ion.
The atomic number of oxygen is 8.
The electronic configuration of Oxygen is
1s^2 2s^2 2p^4
The charge of oxide ion is —2, which means an Oxygen atom gained 2 extra electrons. So,this two extra electrons will be attached the last shell's orbital (2p).
So, the electronic configuration of oxide ion is
1s^2 2s^2 2p^6
When any oxygen atom attach with any metal, oxygen atom gains two electrons from metal and forms oxide ion. In this attachment Ionic bond is formed Between oxygen and metal ion.
Example :CaO
Calcium atom donated two electrons & formed Ca^2+ (Calcium ion).Also gained the electronic configuration of inert gas (Ar)
Oxygen atom gained those two electrons & formed O^2– (Oxide ion). Also gained electronic configuration of inert gas (Ne)
Ca^2+ + O^2- → CaO (Calcium oxide)
Here,Ionic bond is formed between calcium & oxygen.
ankit singh
askIITians Faculty 614 Points
4 years ago

O2−:

The atomic number of O=8=number of electrons

Number of electrons in O2 are 8+2=10

Electronic configuration will be 1s22s22p6