If the electronegativities of H , N , P , As , Sb are 2.1 , 3 , 2.1 , 2 , 1.9 then arrange in order of decreasing polarity of bonds in SbH 3 , AsH 3 , PH 3 and NH 3 .

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Piyush Kumar Behera · Answer

The corect answer to the question is NH 3 > SbH 3 > AsH 3 > PH 3 The polarity of a bond can rougly be said as directly proportional to the difference in electronegativity between the two species in the molecule. Here I have arranged the order on the basis of magnitude of difference of electronegativity in the given molecules I hope it Helps!! Regards Piyush Kumar Behera

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If the electronegativities of H , N , P , As , Sb are 2.1 , 3 , 2.1 , 2 , 1.9 then arrange in order of decreasing polarity of bonds in SbH 3 , AsH 3 , PH 3 and NH 3 .

If the electronegativities of H , N , P , As , Sb are 2.1 , 3 , 2.1 , 2 , 1.9 then arrange in order of decreasing polarity of bonds in SbH₃, AsH₃ , PH₃and NH₃ .

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If the electronegativities of H , N , P , As , Sb are 2.1 , 3 , 2.1 , 2 , 1.9 then arrange in order of decreasing polarity of bonds in SbH 3 , AsH 3 , PH 3 and NH 3 .

If the electronegativities of H , N , P , As , Sb are 2.1 , 3 , 2.1 , 2 , 1.9 then arrange in order of decreasing polarity of bonds in SbH3 , AsH3 , PH3 and NH3 .

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If the electronegativities of H , N , P , As , Sb are 2.1 , 3 , 2.1 , 2 , 1.9 then arrange in order of decreasing polarity of bonds in SbH₃, AsH₃ , PH₃and NH₃ .