sambit
Last Activity: 8 Years ago
the question asked is independent event
probability of selection of a is ¼ and probability of b is 1/6
probability of their union is probability of a+probability of b-probability of a intersection b
it is from set theory
probability of a intersection b is product of probability of a and probability of b
p(a union b)=(1/4)+(1/6)-(1/4)*(1/6)=9/24
probability of their not being selected is (1 – p(a union b))=1 -(9/24)=15/24