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Q = the event that B is selected.
Given that P(P) = 1/4 and P(Q) = 1/6
We know that P' is the event that A does not get selected and Q' is the event that B does not get selected
Probability that none of them are selected =P(P'∩Q') (∵ Reference : Algebra of Events) =P(P').P(Q') (∵ Here A and B are Independent Events and refer theorem on independent events)
=[ 1 – P(P)][ 1 – P(Q)]
=1−(1/4) x 1−(1/6)
=(3/4)×(5/6)=5/8
HENCE THE ANSWER IS 5/8
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