sinB = cos(B-45), where B and (B-45) are acute angles.Find the value of the angle B?
sinB = cos(B-45), where B and (B-45) are acute angles.Find the value of the angle B?
Malyarpita Singh , 7 Years ago
Grade 10
10 grade maths> sinB = cos(B-45), where B and (B-45) are ...
2 Answers
Arun
Dear student
By allied angles conversion
90 – B = B – 45
2B = 135
hence B = 67.5 degree
hope it helps
Regards
Arun
Approved Last Activity: 7 Years ago
Rishit Dagli
We know,
If sin a = cos b
Then 90-a=b
Therefore,
90-b=b-45
2b=135
Hope it helps
Rishit Dagli
b=135/2
b=67.5 degrees
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